A Speedy Tortoise Can Run With a Speed of 10 Cm/s

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Question 214298: I am having problem figuring out how to solve this trouble and any aid would be appreciated. This problem is not from a text book and is ane that my professor create himself.
A speedy tortoise can run with a speed of 10 cm/sec and a hare tin run xx times as fast. If they both start at the same fourth dimension, merely the hare stops for 2 minutes to rest, the tortoise wins by 20cm.
1. How long does the race have?
2. What is the length of the race?
Establish 2 solutions by stanbon, scott8148:
Answer by stanbon(75887) (Show Source):
Y'all can put this solution on YOUR website!
A speedy tortoise tin run with a speed of 10 cm/sec and a hare can run 20 times equally fast. If they both get-go at the same time, but the hare stops for 2 minutes to residual, the tortoise wins by 20cm.
1. How long does the race have?
Tortoise Information:
charge per unit = 10 cm/sec ; distance = x cm ; fourth dimension = x/10 seconds
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Hare DATA:
rate = 200 cm/sec ; distance = (x-xx) cm ; time = (ten-20)/200 sec
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Equation
Hare time + 120 seconds = tortoise fourth dimension
(x-twenty)/200 + 120 = x/10
Multiply thru by 200 to become:
x-20 + 200*120 = 20x
19x = 200*120 -xx
ten = 1262.xi cm (length of the race)
x/10 = 126.21 seconds (time of the race)
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Cheers,
Stan H.
2. What is the length of the race?

Respond by scott8148(6628) (Show Source):
You can put this solution on YOUR website!
one. t * x = [(t - 120) * 200] + 20 ___ fourth dimension is in seconds
10t = 200t - 23980 ___ 23980 = 190t ___ 126.two = t (approx)

2. d = x * t = x * 126.ii = 1262 cm